The weight of lolly pops in a box is normally distributed with a mean of 5kg and a standard deviation of 0.1kg. What is the probability that a randomly selected box of lolly pops weighs between 5.03 and 5.16 kg?

Answer 1

(5.03-5.0)/0.1 = 0.3 S.D.
(5.16-5.0)/0.1 = 1.6 S.D.

Look up the z tables to find what probability (of a normal distribution) is between 0.3 and 1.6 standard deviations.
I get 0.4452-0.1179=0.3273