The weight of an ant averages about 3×10−6 kg. There are about 1×1016 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation

11 answers

To find the approximate weight of all the ants in the world, you can multiply the average weight of an ant by the total number of ants:

\[ \text{Total weight} = \text{weight of one ant} \times \text{number of ants} \]

Substituting the given values:

\[ \text{Total weight} = (3 \times 10^{-6} \text{ kg}) \times (1 \times 10^{16}) \]

Now, apply the multiplication:

\[ \text{Total weight} = 3 \times 1 \times 10^{-6} \times 10^{16} = 3 \times 10^{10} \text{ kg} \]

So, the approximate weight of all the ants in the world is:

\[ \boxed{3 \times 10^{10}} \text{ kg} \]

The average human heart beats about 3.5×107 times per year. The current population of Massachusetts is about 7×106 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place

To find the total number of heartbeats that occur in Massachusetts per year, you can multiply the average number of heartbeats per person by the population of Massachusetts:

\[ \text{Total heartbeats} = \text{heartbeats per person per year} \times \text{population} \]

Substituting the given values:

\[ \text{Total heartbeats} = (3.5 \times 10^{7} \text{ beats/year}) \times (7 \times 10^{6} \text{ people}) \]

Now, apply the multiplication:

\[ \text{Total heartbeats} = 3.5 \times 7 \times 10^{7} \times 10^{6} \]

Calculating \(3.5 \times 7\):

\[ 3.5 \times 7 = 24.5 \]

Now, combine the powers of ten:

\[ \text{Total heartbeats} = 24.5 \times 10^{7 + 6} = 24.5 \times 10^{13} \]

To express \(24.5\) in proper scientific notation, we can write it as \(2.45 \times 10^{1}\):

\[ \text{Total heartbeats} = 2.45 \times 10^{1} \times 10^{13} = 2.45 \times 10^{14} \]

Thus, the total number of heartbeats that occur in Massachusetts per year is:

\[ \boxed{2.45 \times 10^{14}} \]

The sun generates about 4×1026 joules of energy every second. There are about 3.15×107 seconds in a year. About how many joules of energy does the sun generate in a year? Write the answer in scientific notation. Express the answer to the exact decimal place

To find the total energy generated by the Sun in a year, we need to multiply the energy generated per second by the total number of seconds in a year.

Given:

  • Energy generated by the Sun per second: \(4 \times 10^{26}\) joules
  • Number of seconds in a year: \(3.15 \times 10^{7}\) seconds

The total energy generated in a year is calculated as follows:

\[ \text{Total energy} = \text{Energy per second} \times \text{Number of seconds in a year} \]

Substituting in the values:

\[ \text{Total energy} = (4 \times 10^{26} \text{ joules/second}) \times (3.15 \times 10^{7} \text{ seconds}) \]

Now, multiply the coefficients and add the exponents:

\[ \text{Total energy} = 4 \times 3.15 \times 10^{26} \times 10^{7} \]

Calculating \(4 \times 3.15\):

\[ 4 \times 3.15 = 12.6 \]

Then combine the powers of ten:

\[ \text{Total energy} = 12.6 \times 10^{26 + 7} = 12.6 \times 10^{33} \]

To express \(12.6\) in scientific notation, we can write it as \(1.26 \times 10^{1}\):

\[ \text{Total energy} = 1.26 \times 10^{1} \times 10^{33} = 1.26 \times 10^{34} \]

Thus, the total energy generated by the Sun in one year is:

\[ \boxed{1.26 \times 10^{34}} \text{ joules} \]

The average newborn weighs 7.5 pounds. About 4.1×106 babies are born in the United States every year. What is the approximate total weight in pounds of all the babies born in the U.S. in a year? Write the answer in scientific notation, expressed to the exact decimal place

To find the total weight of all the newborn babies in the U.S. born in a year, you can multiply the average weight of a newborn by the total number of babies born in that year.

Given:

  • Average weight of a newborn: \(7.5\) pounds
  • Number of babies born per year: \(4.1 \times 10^{6}\)

The total weight can be calculated as follows:

\[ \text{Total weight} = \text{Average weight} \times \text{Number of babies} \]

Substituting in the values:

\[ \text{Total weight} = (7.5 \text{ pounds}) \times (4.1 \times 10^{6} \text{ babies}) \]

Now, perform the multiplication:

\[ \text{Total weight} = 7.5 \times 4.1 \times 10^{6} \]

Calculating \(7.5 \times 4.1\):

\[ 7.5 \times 4.1 = 30.75 \]

Now we combine it with the power of ten:

\[ \text{Total weight} = 30.75 \times 10^{6} \]

To express \(30.75\) in scientific notation, we rewrite it as \(3.075 \times 10^{1}\):

\[ \text{Total weight} = 3.075 \times 10^{1} \times 10^{6} = 3.075 \times 10^{7} \]

Thus, the approximate total weight in pounds of all the babies born in the U.S. in a year is:

\[ \boxed{3.075 \times 10^{7}} \text{ pounds} \]

In a given year, about 1.52×1010 pieces of first-class mail are delivered in the U.S. If each piece of mail carries a stamp costing $0.55, what is the total cost in dollars to deliver all the pieces? Write the answer in scientific notation, expressed to the exact decimal place

To find the total cost of delivering all the pieces of first-class mail, we can multiply the number of pieces of mail by the cost of a stamp per piece.

Given:

  • Number of pieces of first-class mail: \(1.52 \times 10^{10}\)
  • Cost of a stamp per piece: \(0.55\) dollars

The total cost can be calculated as follows:

\[ \text{Total cost} = \text{Number of pieces} \times \text{Cost per piece} \]

Substituting in the values:

\[ \text{Total cost} = (1.52 \times 10^{10}) \times (0.55) \]

We can perform the multiplication of the coefficients:

\[ 1.52 \times 0.55 = 0.836 \]

Now, we combine it with the power of ten:

\[ \text{Total cost} = 0.836 \times 10^{10} \]

To express \(0.836\) in scientific notation, we rewrite it as \(8.36 \times 10^{-1}\):

\[ \text{Total cost} = 8.36 \times 10^{-1} \times 10^{10} = 8.36 \times 10^{9} \]

Thus, the total cost in dollars to deliver all the pieces of first-class mail is:

\[ \boxed{8.36 \times 10^{9}} \text{ dollars} \]

What is 5.5×104 multiplied by 2.2×10−8 ? Write the answer in scientific notation

To multiply \(5.5 \times 10^{4}\) by \(2.2 \times 10^{-8}\), we can multiply the coefficients and then add the exponents of the powers of ten.

First, let's calculate the coefficients:

\[ 5.5 \times 2.2 = 12.1 \]

Next, let's add the exponents:

\[ 10^{4} \times 10^{-8} = 10^{4 + (-8)} = 10^{-4} \]

Now, combine the results:

\[ 12.1 \times 10^{-4} \]

To express \(12.1\) in scientific notation, we rewrite it as \(1.21 \times 10^{1}\):

\[ 12.1 \times 10^{-4} = 1.21 \times 10^{1} \times 10^{-4} = 1.21 \times 10^{-3} \]

Thus, the result of \(5.5 \times 10^{4}\) multiplied by \(2.2 \times 10^{-8}\) is:

\[ \boxed{1.21 \times 10^{-3}} \]