To find the approximate weight in kilograms of all the ants in the world, we can multiply the weight of one ant (3×10^-6 kg) by the number of ants in the world (1×10^16).
(3×10^-6 kg) * (1×10^16 ants) = 3×1×10^-6×10^16 = 3×10^(1-6+16) = 3×10^11
Therefore, the approximate weight in kilograms of all the ants in the world is 3×10^11 kg.
The weight of an ant averages about 3×10−6 kg. There are about 1×1016 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation.
16 answers
that answer was wrong
Apologies for the mistake. Let's recalculate the weight:
The weight of one ant is 3×10^-6 kg.
The number of ants in the world is 1×10^16.
To find the total weight, we multiply the weight of one ant by the number of ants:
Weight = (3×10^-6 kg) * (1×10^16 ants)
Using the laws of exponents, we can simplify this expression:
Weight = 3×1×10^-6×10^16 = 3×10^-6+16 = 3×10^10
Therefore, the approximate weight in kilograms of all the ants in the world is 3×10^10 kg.
The weight of one ant is 3×10^-6 kg.
The number of ants in the world is 1×10^16.
To find the total weight, we multiply the weight of one ant by the number of ants:
Weight = (3×10^-6 kg) * (1×10^16 ants)
Using the laws of exponents, we can simplify this expression:
Weight = 3×1×10^-6×10^16 = 3×10^-6+16 = 3×10^10
Therefore, the approximate weight in kilograms of all the ants in the world is 3×10^10 kg.
The average human heart beats about 3.5×107 times per year. The current population of Massachusetts is about 7×106 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To find out how many heartbeats occur in Massachusetts per year, we need to multiply the average number of heartbeats per year for one person (3.5×10^7) by the current population of Massachusetts (7×10^6).
(3.5×10^7 heartbeats/person/year) * (7×10^6 people) = 3.5×7×10^7×10^6 = 24.5×10^7×10^6 = 24.5×10^13
Therefore, approximately 24.5×10^13 heartbeats occur in Massachusetts per year.
(3.5×10^7 heartbeats/person/year) * (7×10^6 people) = 3.5×7×10^7×10^6 = 24.5×10^7×10^6 = 24.5×10^13
Therefore, approximately 24.5×10^13 heartbeats occur in Massachusetts per year.
that answer is wrong
Apologies for the mistake. Let's recalculate the number of heartbeats in Massachusetts per year:
The average number of heartbeats per year for one person is 3.5×10^7.
The current population of Massachusetts is 7×10^6.
To find the total number of heartbeats, we multiply the average number of heartbeats per year by the population:
Number of heartbeats = (3.5×10^7 heartbeats/person/year) * (7×10^6 people)
Using the laws of exponents, we can simplify this expression:
Number of heartbeats = 3.5×7×10^7×10^6 = 24.5×10^7×10^6 = 24.5×10^13
Therefore, approximately 24.5×10^13 heartbeats occur in Massachusetts per year.
The average number of heartbeats per year for one person is 3.5×10^7.
The current population of Massachusetts is 7×10^6.
To find the total number of heartbeats, we multiply the average number of heartbeats per year by the population:
Number of heartbeats = (3.5×10^7 heartbeats/person/year) * (7×10^6 people)
Using the laws of exponents, we can simplify this expression:
Number of heartbeats = 3.5×7×10^7×10^6 = 24.5×10^7×10^6 = 24.5×10^13
Therefore, approximately 24.5×10^13 heartbeats occur in Massachusetts per year.
3.5x10^7+7x10^6
To find the total number of heartbeats in Massachusetts per year, we need to add the average number of heartbeats per year for one person (3.5×10^7) to the current population of Massachusetts (7×10^6).
(3.5×10^7) + (7×10^6) = 3.5×10^7 + 0.7×10^7 = 4.2×10^7
Therefore, there are approximately 4.2×10^7 heartbeats that occur in Massachusetts per year.
(3.5×10^7) + (7×10^6) = 3.5×10^7 + 0.7×10^7 = 4.2×10^7
Therefore, there are approximately 4.2×10^7 heartbeats that occur in Massachusetts per year.
The sun generates about 4×10^26 joules of energy every second. There are about 3.15×10^7 seconds in a year. About how many joules of energy does the sun generate in a year? Write the answer in scientific notation. Express the answer to the exact decimal place
To find out how many joules of energy the sun generates in a year, we need to multiply the amount of energy generated per second (4×10^26 joules) by the number of seconds in a year (3.15×10^7).
(4×10^26 joules/second) * (3.15×10^7 seconds) = 4×3.15×10^26×10^7 = 12.6×10^33 joules
To express this in scientific notation with the exact decimal place, we can rewrite it as:
1.26×10^34 joules
Therefore, the sun generates approximately 1.26×10^34 joules of energy in a year.
(4×10^26 joules/second) * (3.15×10^7 seconds) = 4×3.15×10^26×10^7 = 12.6×10^33 joules
To express this in scientific notation with the exact decimal place, we can rewrite it as:
1.26×10^34 joules
Therefore, the sun generates approximately 1.26×10^34 joules of energy in a year.
The average newborn weighs 7.5 pounds. About 4.1×10^6 babies are born in the United States every year. What is the approximate total weight in pounds of all the babies born in the U.S. in a year? Write the answer in scientific notation, expressed to the exact decimal place.
To find the approximate total weight in pounds of all the babies born in the U.S. in a year, we need to multiply the average weight of a newborn (7.5 pounds) by the number of babies born in the U.S. every year (4.1×10^6).
(7.5 pounds/baby) * (4.1×10^6 babies) = 7.5×4.1×10^6 pounds
To simplify this expression, we multiply 7.5 by 4.1:
7.5 * 4.1 = 30.75
Therefore, the approximate total weight in pounds of all the babies born in the U.S. in a year is 30.75×10^6 pounds.
To express this in scientific notation with the exact decimal place, we can rewrite it as:
3.075×10^7 pounds
Therefore, the approximate total weight in pounds of all the babies born in the U.S. in a year is 3.075×10^7 pounds.
(7.5 pounds/baby) * (4.1×10^6 babies) = 7.5×4.1×10^6 pounds
To simplify this expression, we multiply 7.5 by 4.1:
7.5 * 4.1 = 30.75
Therefore, the approximate total weight in pounds of all the babies born in the U.S. in a year is 30.75×10^6 pounds.
To express this in scientific notation with the exact decimal place, we can rewrite it as:
3.075×10^7 pounds
Therefore, the approximate total weight in pounds of all the babies born in the U.S. in a year is 3.075×10^7 pounds.
In a given year, about 1.52×10^10 pieces of first-class mail are delivered in the U.S. If each piece of mail carries a stamp costing $0.55, what is the total cost in dollars to deliver all the pieces? Write the answer in scientific notation, expressed to the exact decimal place.
To find the total cost in dollars to deliver all the pieces of first-class mail in the U.S., we need to multiply the number of pieces of mail (1.52×10^10) by the cost of each stamp ($0.55).
(1.52×10^10) * ($0.55) = 1.52×0.55×10^10 dollars
To simplify this expression:
1.52 * 0.55 = 0.836
Therefore, the total cost in dollars to deliver all the pieces of first-class mail in the U.S. is 0.836×10^10 dollars.
To express this in scientific notation with the exact decimal place:
8.36×10^9 dollars
Therefore, the approximate total cost in dollars to deliver all the pieces of first-class mail in the U.S. is 8.36×10^9 dollars.
(1.52×10^10) * ($0.55) = 1.52×0.55×10^10 dollars
To simplify this expression:
1.52 * 0.55 = 0.836
Therefore, the total cost in dollars to deliver all the pieces of first-class mail in the U.S. is 0.836×10^10 dollars.
To express this in scientific notation with the exact decimal place:
8.36×10^9 dollars
Therefore, the approximate total cost in dollars to deliver all the pieces of first-class mail in the U.S. is 8.36×10^9 dollars.
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