The weight of a body varies inversely as the square of its distance from the center of the earth. If the radius of the earth is 4000 mi, how much would a 200 lb man weigh 1000 mi above the surface of the earth?

Answer 1

w = k(1/d^2)

when d = 4000 , w = 200
200 = k(1/16000000)
k = 200(16000000)

when d = 5000
w = 200(16000000)/5000^2 = 128

Answer 2

The weight variation equation should be written as
w = 3200000000/d^2
before evaluating the weight for a distance of 5000 miles.

Answer 3

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Answer 4

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