The water storage tank has a diameter of 0.5m and contains 150L of water.
You find a small hole rusted in the base, with a diameter of 10mm. what is the velocity of the water flowing out of the hole?
So, i feel like I need to somehow use both Bernoullis equation and continuity equation to get the answer.
Assuming the tank is a cyliner using the equation V=pi*R2*h=pi*(0.5)2*(0.15), h=0.19m.
Also using continuity if V1A1=V2A2
V1=0.0004V2
substituting all these into both sides of Bernoullis makes sense, except I'm not sure what the pressure is..
if I just assume the pressure is the same and remove it from both sides of the equation the answer is 3.72m/s when the answe is actually 3.9m/s, so there must be something missing.
Please help!
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