To find the water level of the river at the end of summer, we need to add the two drops in water level.
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The initial water level is 1 1/2 meters below sea level, which can be expressed as: \[ 1 \frac{1}{2} = \frac{3}{2} \text{ meters below sea level} \]
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During the summer, the river drops another 2 1/3 meters below sea level, which can be expressed as: \[ 2 \frac{1}{3} = \frac{7}{3} \text{ meters below sea level} \]
Now, we need to add these two values to find the total drop below sea level: \[ \frac{3}{2} + \frac{7}{3} \]
To add these fractions, we first need a common denominator. The least common multiple of 2 and 3 is 6.
Converting both fractions to have the same denominator: \[ \frac{3}{2} = \frac{3 \times 3}{2 \times 3} = \frac{9}{6} \] \[ \frac{7}{3} = \frac{7 \times 2}{3 \times 2} = \frac{14}{6} \]
Now, add the two fractions: \[ \frac{9}{6} + \frac{14}{6} = \frac{9 + 14}{6} = \frac{23}{6} \]
Thus, the total water level at the end of summer is: \[ \frac{23}{6} \text{ meters below sea level} \]
To express this as a mixed number, we perform the division: \[ 23 \div 6 = 3 \text{ R } 5 \] So, \(\frac{23}{6} = 3 \frac{5}{6}\).
Therefore, the final water level at the end of summer is: \[ \text{The water level is } 3 \frac{5}{6} \text{ meters below sea level.} \]
For the answer format requested: \[ \text{The water level is } 3.8333 \text{ meters below sea level (or as a fraction } 3 \frac{5}{6} \text{).} \]
So, the water level is \(3 \frac{5}{6} \text{ meters below sea level or } 3.8333 \text{ meters below sea level.}\)