, 0.33m.
N = 9.2*10^7/(2*pi*0.33)
N = 2.8*10^8 revolutions
The warranty on a new tire says that an automobile can travel for a distance of 92,000km before the tire wears out. The radius of the tire is 0.33m. How many revolutions does the tire make before wearing out?
hello CJ I think we are in the same class. I had sent you an e-mail.
92,000*10^3 m = N * (tire circumference)
= 2*pi*R N = 9.2*10^7.
Solve for the number of turns, N.
R is the radius in meters
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