To solve this system of equations, we can use the elimination method.
First, we can multiply the first equation by 2 and the second equation by 3 to make the coefficients of either the hots dogs or cheeseburgers the same:
8h - 6c = 47.50
18h - 6c = 75
Now, we can subtract the first equation from the second to eliminate c:
10h = 27.50
Next, we divide both sides by 10 to solve for h:
h = 2.75
Now that we have the price of a hot dog, we can substitute this value back into the first equation to solve for the price of a cheeseburger:
4(2.75) - 3c = 23.75
11 - 3c = 23.75
-3c = 12.75
c = 4.25
Therefore, the price of a hot dog is $2.75 and the price of a cheeseburger is $4.25.
The Walker and Baldwin families ordered lunch at the refreshment stand at the basketball game. The Walker family ordered 4 hot dogs and 3 cheeseburgers and paid $23.75. The Baldwin family ordered 6 hots dogs and 2 cheeseburgers and paid $25. Write a system of equations using h
for hot dogs and c
for cheeseburgers.(1 point)
Responses
4h − 3c = 23.75
and 6h − 2c = 25
4h − 3c = 23.75
and 6h − 2c = 25
4h + 3c = 23.75
and 6h + 2c = 25
4h + 3c = 23.75
and 6h + 2c = 25
h + c = 23.75
and h + c = 25
h + c = 23.75
and h + c = 25
7c = 23.75
and 8h = 25
7c = 23.75
and 8h = 25
Question 2
What are the prices of a hot dog and a cheeseburger?
This question requires you to show your work.
(2 points)
$4.25 $2.00 $5.00 $2.75
hot dog
cheeseburger
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1 answer