The Walker and Baldwin families ordered lunch at the refreshment stand at the basketball game. The Walker family ordered 4 hot dogs and 3 cheeseburgers and paid $23.75. The Baldwin family ordered 6 hots dogs and 2 cheeseburgers and paid $25. Write a system of equations using h for hot dogs and c for cheeseburgers.(1 point)

Question

Responses

h + c = 23.75 and h + c = 25
h + c = 23.75 and h + c = 25

7c = 23.75 and 8h = 25
7c = 23.75 and 8h = 25

4h + 3c = 23.75 and 6h + 2c = 25
4h + 3c = 23.75 and 6h + 2c = 25

4h − 3c = 23.75 and 6h − 2c = 25

Answer 1

4h + 3c = 23.75 and 6h + 2c = 25

This is the correct system of equations using h for hot dogs and c for cheeseburgers.

Answer 2

What are the prices of a hot dog and a cheeseburger?

This question requires you to show your work.

(2 points)
$4.25 $2.00 $5.00 $2.75
cheeseburger

hot dog

Answer 3

To find the prices of a hot dog and a cheeseburger, we can solve the system of equations:

4h + 3c = 23.75
6h + 2c = 25

Let's first eliminate one variable by multiplying the first equation by 2 and the second equation by 3:

8h + 6c = 47.50
18h + 6c = 75

Subtract the first equation from the second equation to eliminate c:

18h + 6c - 8h - 6c = 75 - 47.50
10h = 27.50
h = 2.75

Now plug the value of h back into the first equation:

4(2.75) + 3c = 23.75
11 + 3c = 23.75
3c = 12.75
c = 4.25

Therefore, the price of a hot dog is $2.75 and the price of a cheeseburger is $4.25.