The Walker and Baldwin families ordered lunch at the refreshment stand at the basketball game. The Walker family ordered 4 hot dogs and 3 cheeseburgers and paid $23.75. The Baldwin family ordered 6 hots dogs and 2 cheeseburgers and paid $25. Write a system of equations using h

Question

for hot dogs and c
for cheeseburgers.(1 point)
Responses

4h + 3c = 23.75
and 6h + 2c = 25
4h + 3c = 23.75
and 6h + 2c = 25

7c = 23.75
and 8h = 25
7c = 23.75
and 8h = 25

h + c = 23.75
and h + c = 25
h + c = 23.75
and h + c = 25

4h − 3c = 23.75
and 6h − 2c = 25
4h − 3c = 23.75
and 6h − 2c = 25
Question 2
What are the prices of a hot dog and a cheeseburger

Answer 1

Using the system of equations:

4h + 3c = 23.75
6h + 2c = 25

Solving for h and c:

From the first equation:
4h + 3c = 23.75
4h = 23.75 - 3c
h = (23.75 - 3c)/4

Substitute h back into the second equation:
6((23.75 - 3c)/4) + 2c = 25
14.25 - 1.5c + 2c = 25
0.5c = 10.75
c = 21.5

Now substitute the value of c back into the first equation to find h:
4h + 3(21.5) = 23.75
4h + 64.5 = 23.75
4h = 23.75 - 64.5
4h = -40.75
h = -10.19

Therefore, the price of a hot dog is $10.19 and the price of a cheeseburger is $21.50.