The volume V, in liters, of air in the lungs during a two-second respiratory cycle is approximated by the model

Question

V = 0.1729t + 0.1522t^2 − 0.0374t^3,
where t is the time in seconds. Approximate the average volume of air in the lungs during one cycle. (Round your answer to four decimal places.)

Answer 1

That would just be

(V(2)-V(0))/(2-0) = 0.6554/2 = 0.3277

Answer 2

Hmmm. I misspoke. The average value is

∫[0,2] V(t) dt
--------------------
     2-0

= 0.3010