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The volume of this cone is 103.62 cubic millimeters. What is the height of this cone? Use 𝜋 ≈ 3.14 and round your answer to th...Question
The volume of this cone is 376.8 cubic millimeters. What is the height of this cone?
Use 𝜋 ≈ 3.14 and round your answer to the nearest hundredth.
6 mm
h ≈
millimeters
Use 𝜋 ≈ 3.14 and round your answer to the nearest hundredth.
6 mm
h ≈
millimeters
Answers
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Answered by
GPT-4o mini
To find the height of the cone, we can use the formula for the volume of a cone:
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height.
We are given:
- Volume \( V = 376.8 \) cubic millimeters,
- \( \pi \approx 3.14 \).
We also need to note that from the problem you provided, it seems like the radius is not mentioned. However, if you assume a radius (for example, given as 6 mm, or if that's assumed), you can then solve for the height. I'll proceed with using \( r = 6 \) mm.
First, let's plug in the values into the formula:
\[
376.8 = \frac{1}{3} \times 3.14 \times (6)^2 \times h
\]
Calculating \( 6^2 \):
\[
6^2 = 36
\]
Now substitute this into the volume formula:
\[
376.8 = \frac{1}{3} \times 3.14 \times 36 \times h
\]
Calculating \( \frac{1}{3} \times 3.14 \times 36 \):
\[
\frac{1}{3} \times 3.14 \times 36 = \frac{113.04}{3} = 37.68
\]
Now the equation becomes:
\[
376.8 = 37.68h
\]
To solve for \( h \), divide both sides by \( 37.68 \):
\[
h = \frac{376.8}{37.68} \approx 10
\]
Rounded to the nearest hundredth, the height \( h \) is:
\[
h \approx 10.00 \text{ mm}
\]
Thus, the height of the cone is approximately **10.00 millimeters**. If the radius was something other than 6 mm, please provide that information for accurate calculations.
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height.
We are given:
- Volume \( V = 376.8 \) cubic millimeters,
- \( \pi \approx 3.14 \).
We also need to note that from the problem you provided, it seems like the radius is not mentioned. However, if you assume a radius (for example, given as 6 mm, or if that's assumed), you can then solve for the height. I'll proceed with using \( r = 6 \) mm.
First, let's plug in the values into the formula:
\[
376.8 = \frac{1}{3} \times 3.14 \times (6)^2 \times h
\]
Calculating \( 6^2 \):
\[
6^2 = 36
\]
Now substitute this into the volume formula:
\[
376.8 = \frac{1}{3} \times 3.14 \times 36 \times h
\]
Calculating \( \frac{1}{3} \times 3.14 \times 36 \):
\[
\frac{1}{3} \times 3.14 \times 36 = \frac{113.04}{3} = 37.68
\]
Now the equation becomes:
\[
376.8 = 37.68h
\]
To solve for \( h \), divide both sides by \( 37.68 \):
\[
h = \frac{376.8}{37.68} \approx 10
\]
Rounded to the nearest hundredth, the height \( h \) is:
\[
h \approx 10.00 \text{ mm}
\]
Thus, the height of the cone is approximately **10.00 millimeters**. If the radius was something other than 6 mm, please provide that information for accurate calculations.
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