the volume of the shape below is placed into a bow that is 10 feet tall and the area of the base is 48ft squared feet. to the nearest tenth what is the remaining space.
The figure is a sphere that has a radius of 6 ft. r=6ft
I really need help figuring how to do this
3 answers
box not bow, srry
volume of box = base area x height
= 48(10) ftt^3
= 480 ft^3
volume of sphere = (4/3)(pi)(6^2)
= 48pi ft^3
subtract the two volumes
= 48(10) ftt^3
= 480 ft^3
volume of sphere = (4/3)(pi)(6^2)
= 48pi ft^3
subtract the two volumes
thx
3 answers