the volume of nh3 at stp needed to pass into 30 ml of 1N h2so4 solution to bring down its strength to m/10

Answer 1

Meq of original H2SO4=30×1=30

Meq of H2SO4 after passing NH3=30×0.2=6

Meq of H2SO4 lost =30−6=24

Meq of NH3 passed=Meq of H2SO4 lost

w17×1000=24

WNH3=0.408g

∴ Volume of NH3 at STP=22.4×0.40817

⇒0.5376l

⇒537.6ml

Answer 2

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