The volume of a rectangular box is given by the formula V = lwh, where l is length, w is width, and h is height. What happens to the volume if the length and height are doubled and the width is tripled?

I don't know how to solve this problem at all.

Thank you for your help!

4 answers

new volume = (2h)(2l)(3w) = 12lwh

so the volume is 12 times as big
vol = l*w*h
the question is that
l is doubled to give 2l
h is doubled to give 2h and
w is tripled to give 3h.

so the new vol = (2l)*(2h)*(3w) = 12*l*w*h
so 'new vol' = 12*old vol

Hope that helps
I really don't understand this honors algebra
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