The volume of a gas is 5.80 L, measured at 2.54 atm. What is the pressure of the gas in mmHg if the volume is changed to 9.65 L? The temperature remains constant.

Answer 1

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant. Mathematically, this law can be represented as: P1V1 = P2V2.

Given:
P1 = 2.54 atm
V1 = 5.80 L
V2 = 9.65 L

Now we can plug these values into the equation and solve for P2:

2.54 atm * 5.80 L = P2 * 9.65 L

14.732 atm*L = 9.65 P2

P2 = 14.732 atm*L / 9.65 L

P2 = 1.5278 atm

To convert this pressure to mmHg, we can use the conversion factor 1 atm = 760 mmHg:

1.5278 atm * 760 mmHg/atm = 1162.17 mmHg

Therefore, the pressure of the gas in mmHg when the volume is changed to 9.65 L is 1162.17 mmHg.