The volume of a fixed mass of gas at S..T.P is 130cm3, what is the temperature if the new the pressure is 1860mmHg and the volume doubled.

Answer 1

2*130*1860/T = 130*760/273.15
T = 1337 K

or,
2V*2.45P/T' = PV/T
T' = 4.89T = 4.89*273.15 = 1337 K

Answer 2

P1V1/T1 = P2V2/T2
P1 = 760 mm Hg
V1 = 130 cc
T1 = 273 K
P2 = 1860 mm Hg
V2 = 260 cc
T2 = ? K\
Post your work if you get stuck.