The volume of a 3.60L sample of gas at 27degrees Celsius is reduced at constant pressure of 3.00L. What is the final temperature?

Answer 1

(V1/T1) = (V2/T2)
Remember that T must be in kelvin.

Answer 2

T2 = 300K(3.00L/3.60L)
= 250K or -27degrees Celsius