Use PV = nRT and solve for n = number of mols. Then n = grams/molar mass. You know n and grams, solve for molar mass.
You can do it another way knowing that an ideal gas at STP will occupy 22.4L.
Therefore, n = 1.15L/22.4L = number of mols, then n = grams/molar mass.
The volume of 3.96g of a gas sample at standard conditions it was found to be 1.15L.Calculate its molecular mass.
2 answers
Solution: n=1.15L/22.4L , n=0.0513 mol , then use n=m/M , M=3.96/0.0513 , ur M=77.13 g/mol , dats all