moles = grams/molar mass
moles = 6.30/84 = 0.075 moles NaHCO3.
M = moles/L
0.150 = 0.075/L
L = 0.075/0.150 = 0.500 L. :-),
The volume of .150 molar NaHCO3 solution that contains 6.30 g of Na2CO3 is...
a. .200 L
b. 0.400 L
c. .500 L
d. 1.60 L
e. 2.5 L
I know the answer is C but I do not understand how. Can someone please help!!! M= moles of solute/liters of solutions.
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