The voltage of an electrochemical cell depends on the redox reaction occurring in the cell. Given a redox reaction below:
Zn(s) + Pb2+(aq) --> Zn2+(aq) + Pb(s)
Pb2+(aq) + 2 e--->Pb(s)Eº = -0.13V
Zn2+(aq) + 2 e--->Zn(s)Eº = -0.76V
Calculate the E.M.F (Voltage) of the cell
1 answer
what is the pH of the solution in anode compartment of the following if the measured cell potential at 25oC is 0.28V