That line must pass through c (2,6) and the midpoint of ab, which is (4,2)
The slope is (6-2)/(2-4) = -2
y = -2 x + b. Now solve for b, by requiring that
6 = (-2)(2) + b
b = 10 Therefore
y = -2x + 10
the vertices of ABC are A(1,1) B(7,3) and C(2,6) write and equation of the line that contains the median from c to ab
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