huh? You can't apply the distance formula?
AB = √((5+2)^2+(4-3)^2) = √(49+1) = √50
CD = √((-3-4)^2+(-4+3)^2) = √(49+1) = √50
So, AB=CD
Now do the same steps for AD and BC.
The vertices of a quadrilateral are A(-2,3), B(5,4), C(4, -3) and D(-3, -4).
Prove that ABCD is a rhombus. Find the area of ABCD.
Formula to find length:
d = √(x2 - x1)^2 + (y2-y1)^2
Please show working out, thanks.
1 answer
1 answer