The vertices of a quadrilateral are A(-2,3), B(5,4), C(4, -3) and D(-3, -4).

Prove that ABCD is a rhombus. Find the area of ABCD.

Formula to find length:

d = √(x2 - x1)^2 + (y2-y1)^2

Please show working out, thanks.

1 answer

huh? You can't apply the distance formula?

AB = √((5+2)^2+(4-3)^2) = √(49+1) = √50
CD = √((-3-4)^2+(-4+3)^2) = √(49+1) = √50
So, AB=CD

Now do the same steps for AD and BC.