the velocity of particle moving along the x axis is given for t>0 by vx=(32t-2t3) m/s, where t is in s. what is the acceleration of the particles when (after t=0) it achieves its maximum displacement in the positive x direction?

Answer 1

max displacement is when v=0, so find t when that is true
a = dv/dt = 32 - 6t^2