huh? a = dv/dt = 2
the acceleration is a constant 2 cm/s^2, so it will never be 5.
The velocity of a particle is given by v=2x+1 cms^-1. If the particle is initially at the origin, find what the displacement will be when the acceleration is 5 cm s^-2.
Answer 0.75cm
3 answers
Thats what the Q says though. I dont know how acc can be 5
maybe it means when v=5.
In that case, t=2
so s = x^2+x = 2^2+2 = 6
Hmmm. Definitely not 0.75
so, when is x^2+x = 3/4?
when x = 1/2
make of that what you will
In that case, t=2
so s = x^2+x = 2^2+2 = 6
Hmmm. Definitely not 0.75
so, when is x^2+x = 3/4?
when x = 1/2
make of that what you will
0 answers