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The velocity of a 2.5 kg block sliding down a frictionless inclined plane is found to be 1.58 m/s. 1.40 s later, it has a velocity of 7.32 m/s.

What is the angle of the plane with respect to the horizontal (in degrees)?

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acceleration= change velocity/time

force down= mass*acceleration

mgSinTheta= m*a
solve for theta.

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