the velocity at light gate A is 0.20 m/s, the acceleration is 0.32 m/s^2, and the time taken is 1.9s. calculate the velocity of the ball at light gate B.

Question

explan and show your working.

Answer 1

Velocity at light gate B = Velocity at light gate A + Acceleration x Time

Velocity at light gate B = 0.20 m/s + 0.32 m/s^2 x 1.9s

Velocity at light gate B = 0.908 m/s

Answer 2

wouldn't it be 0.808m/s then?

0.20 m/s + 0.32 m/s^2 x 1.9s according to BIDMAS (and my calculator) is 0.808