(a-5b).(a-b) = 0 ---->
a^2 + 5 b^2 - 6 a.b = 0
a^2 = b^2 = 1 (as a and b are unit vectors), therefore:
a.b = 1
THE VECTORS a - 5b AND a-b ARE PERPENDICULAR. IF a AND b ARE UNIT VECTORS, THEN DETERMINE a dot b
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