Asked by ucieng

The vector position of a 3.80 g particle moving in the xy plane varies in time according to the following equation.

r1=(3i+3j)t+2jt^2

At the same time, the vector position of a 5.35 g particle varies according to the following equation.

r2=3i-2it^2-6jt

For each equation, t is in s and r is in cm. Solve the following when t = 2.60

Find the vector position of the center of mass.(i+j)
Answered by drwls
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Answered by bob
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