the variable à is jointly proportional to the square of b and c of a=307 when b = 2 and c=5 what is the value of a when b=6 and c=6 round your answer to two decimal places if necessary

1 answer

We can set up the equation as follows:

a = k * b^2 * c

Given that a = 307 when b = 2 and c = 5, we can substitute these values into the equation to find the value of k.

307 = k * 2^2 * 5
307 = 20k

Solving for k, we have:
k = 307/20
k = 15.35

Now, we can substitute the new values of b = 6 and c = 6 along with k into the equation to find the value of a:

a = 15.35 * 6^2 * 6
a = 15.35 * 36 * 6
a = 3310.8

Rounding to two decimal places, the value of a is 3310.80.