the vapor pressure of carbon sulfide is 355.6 torr at 25 degrees Celsius. what is the vapor pressure of a solution prepared by dissolving 12.52 g naphthalene (C10H8, 128.2 g/mol) in 125.0 mL CS2 liquid (76.14 g/mol, 1.261 g/mL)? Assume the solution obeys Raoult's law, and treat naphthalene as a nonvolatile solute. what is the torr?

Answer 1

Convert g each to mols and convert to XCS2
Then psolution = XCS2*Po CS2

Post your work if you get stuck and I can help you through it.

Answer 2

I convert the C10H8 and CS2 into moles. im not sure what to do after that

Answer 3

fuick you