Question

The values of a function f(x) are given in the table below:
x=1, f(x)=3
x=2, f(x)=13
x=3. f(x)=8
x=5,f(x)=1
x=8,f(x)=0
x=13, f(x)=5
If f^-1 exists, what is
f^-1((f^-1(5)+f^-1(13))/ f^-1(1))?

I am not quite sure how to do this.

Answer 1

just the way you would evaluate any complicated expression. Start deep and work outward:

f^-1(5) = 13
f^-1(13) = 2
f^-1(1) = 5

So, you have

f^-1((13+2)/5)
=f^-1(3)
= 1