if roots are p,q, r, then the function is (x-p)(x-q)(x-r)
so in this case...
(x+3)(x-2)(x-2)=f(x)
The values for x when f(x) = 0 are:
x=-2 and x=3
My question is:
The function f(x) can be written in the form of a(x-p)(x-q)(x-r)
Write down one possible set of values for p, q, and r?
Now Ive got the correct answer x = -3, 2 and 2
Could you show me step-by step how to end up with those values?
Do you substitute p, q and r with 0 .
1 answer