To express the values that make the equation \(3x^2 + 7 = 10\) true in set notation, we first solve the equation:
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Subtract 7 from both sides: \[ 3x^2 = 10 - 7 \] \[ 3x^2 = 3 \]
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Divide by 3: \[ x^2 = 1 \]
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Take the square root of both sides: \[ x = \pm 1 \]
Thus, the solutions are \(x = -1\) and \(x = 1\).
In set notation, this can be expressed as: \[ {-1, 1} \]
So the correct answer is {-1, 1}.