To find the solution to the equation \( 3x^2 + 7 = 10 \), we first simplify the equation:
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Subtract 7 from both sides: \[ 3x^2 = 10 - 7 \] \[ 3x^2 = 3 \]
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Divide both sides by 3: \[ x^2 = 1 \]
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Take the square root of both sides: \[ x = \pm 1 \]
This means the solutions are \( x = -1 \) and \( x = 1 \).
Using set notation, we express the solution as: \[ { -1, 1 } \]
So, the solution to the equation \( 3x^2 + 7 = 10 \) in set notation is \( { -1, 1 } \).