To find the solution to the equation \( 3x^2 + 7 = 10 \), we first solve for \( x \).
Start by isolating \( x^2 \):
\[ 3x^2 + 7 = 10 \] Subtract 7 from both sides:
\[ 3x^2 = 10 - 7 \] \[ 3x^2 = 3 \] Now, divide both sides by 3:
\[ x^2 = 1 \] Taking the square root of both sides gives:
\[ x = \pm 1 \]
Thus, the solutions are \( x = -1 \) and \( x = 1 \).
To express these solutions in set notation, we can write:
\[ { -1, 1 } \]
So, the solution set in set notation is:
\[ { -1, 1 } \]