The value of y varies directly with x. When y = -12 1/2, x = 50. What is the value of y when x is 11 3/4, rounded to the nearest hundredths?

Can someone please show me how to solve this problem?

2 answers

y = k x

-12.5 = 50 k

-25 = 100 k

k = -1/4

y = -x/4

y = - (47/4) / 4

= - 47/16
since y=kx, y/k = k is constant, so you want y such that

y/(11 3/4) = (-12 1/2)/50
y = -47/16
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