Wait never mind I figured it out.
1/F = F so 1/102 right?
The value of the equilibrium constant (Kp) as represented by the first chemical equation is 1.02 x 102 at 727 °C. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.
2F(g) = F2(g)
F2(g) = 2F(g)
I'm not getting the math here, like how to mortify the first equation to equal it to the second one. [F]/[F]^2 = [F]^2/[F] ?
The answer is 9.8 x 10^-3
2 answers
right.
1/k = 1/1.02 x 10^2 = 9.8 x 10^-3
1/k = 1/1.02 x 10^2 = 9.8 x 10^-3