6535 kJ/2 mol C6H6 = ? kJ/1 mol C2H6.
mols C2H6 in 16.0g = grams/molar mass
Then
kJ heat released = kJ/mol x # mols in 16.0g = ?
The value of ΔH° for the reaction below is - 6535 kJ. __________ kJ of heat are released in the combustion of 16.0 g of
C6H6(l)?
2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O (l)
1 answer
1 answer