df/dx = 1 - c/x^2 = 0
If the minimum is at x = 3, then
c/x^2 = c/9 = 1
c = 9
The value of c for which f(x) = x + c/x has a local minimum at x= 3 is
(a) -9
(b) - 6
(c) -3
(d) 6
(e) 9
2 answers
Hjjk
(a) -9
(b) - 6
(c) -3
(d) 6
(e) 9
2 answers