Let the value of the basketball a year ago be \( x \).
Since the value increased by 10%, we can express the relationship as follows:
\[ x + 0.10x = 253 \]
This simplifies to:
\[ 1.10x = 253 \]
To find \( x \), we divide both sides by 1.10:
\[ x = \frac{253}{1.10} \]
Now, calculating the right side:
\[ x = \frac{253}{1.10} = 230 \]
Thus, the value of the basketball a year ago was \( \boxed{230} \).