The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.

The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours.

How many times more was the electricity used in 1950 than 1902? Express your answer in Scientific Notation.

(1 point)
Responses

Divide coefficients and subtract powers: 7.13×101
Divide coefficients and subtract powers: 7.13×101

Subtract coefficients and divide powers: 1.73×102
Subtract coefficients and divide powers: 1.73×102

Multiply coefficients and add powers: 2.6×1021
Multiply coefficients and add powers: 2.6×1021

Divide coefficients and subtract powers: 1.4 x 102
Divide coefficients and subtract powers: 1.4 x 102

Add coefficients and add powers: 10.33×1020
Add coefficients and add powers: 10.33×1020
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1 answer

To find how many times more electricity was used in 1950 compared to 1902, you divide the consumption in 1950 by the consumption in 1902.

Consumption in 1902: \[ 6.03 \times 10^9 , \text{kWh} \]

Consumption in 1950: \[ 4.3 \times 10^{11} , \text{kWh} \]

Now, we perform the division:

\[ \frac{4.3 \times 10^{11}}{6.03 \times 10^9} \]

First, divide the coefficients:

\[ \frac{4.3}{6.03} \approx 0.712 \]

Next, subtract the powers:

\[ 10^{11 - 9} = 10^2 \]

Combine the results:

\[ 0.712 \times 10^2 \]

To express this in proper scientific notation, we need to adjust \(0.712\):

\[ 0.712 = 7.12 \times 10^{-1} \]

So we can rewrite our result as:

\[ 7.12 \times 10^{-1} \times 10^2 = 7.12 \times 10^{1} \]

Thus, the final answer in scientific notation is:

\[ \boxed{7.12 \times 10^1} \]

This can be rounded to \( 7.13 \times 10^1 \) if necessary, depending on the required precision. In this case, the first response option is the closest to our calculation.