let the tens digit of the original be x
so original number was 10x+4
number reversed = 40+x
10x+4 = 40+x + 45
9x = 81
x = 9
the old was 94, the new one is 49
Their sum = 143
The units digit of a two-digit positive integer is 4. If the tens digit and units digit of the number are switched, the new number is 45 less than the original number. What is the sum of the original and the new number?
1 answer