To find how much the debt increased in the 50-year period, we need to subtract the debt in 1971 from the debt in 2021.
2021 debt - 1971 debt = ($2.9617 × 10^13) - ($3.98 × 10^11)
To subtract the numbers in scientific notation, we need to have the exponents (or powers of ten) be the same. We can rewrite $3.98 × 10^11 as $0.398 × 10^13.
Now we can subtract the two debts:
($2.9617 × 10^13) - ($0.398 × 10^13) = $2.5637 × 10^13
Therefore, the debt increased by $2.5637 × 10^13 in the 50-year period.
The U.S. national debt was $2.9617 × 10^13 in 2021 and $3.98 × 10^11 in 1971. Find how much the debt increased in the 50-year period. (1 point)
Responses
$2.9219×10^11
2.9219 dollars times 10 superscript 11 baseline
$1.0183×10^24
1.0183 dollars times 10 superscript 24 baseline
$2.9219×10^13
2.9219 dollars times 10 superscript 13 baseline
$3.0015×10^13
9 answers
It has to be 1 of the following choices
(a)$2.9219×10^11
(b)$1.0183×10^24
(c)$2.9219×10^13
(d)$3.0015×10^13
(a)$2.9219×10^11
(b)$1.0183×10^24
(c)$2.9219×10^13
(d)$3.0015×10^13
I apologize for the confusion. The correct answer is:
(c) $2.9219×10^13
The U.S. national debt increased by $2.9219×10^13 in the 50-year period from 1971 to 2021.
(c) $2.9219×10^13
The U.S. national debt increased by $2.9219×10^13 in the 50-year period from 1971 to 2021.
The size of a hydrogen atom is about 1.2×10^−10 m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation?(1 point)
Responses
(A) 3.2 ×10^−10 m
(B) 3.2×10^−11 m
(C) 2.72×10^−10 m
(D) 3.2×10^−9 m
Responses
(A) 3.2 ×10^−10 m
(B) 3.2×10^−11 m
(C) 2.72×10^−10 m
(D) 3.2×10^−9 m
To find the difference between the sizes of the hydrogen and oxygen atoms, we need to subtract the size of the hydrogen atom from the size of the oxygen atom.
Size of hydrogen atom: 1.2×10^−10 m
Size of oxygen atom: 0.000000000152 m
To subtract the numbers in scientific notation, we need to have the exponents be the same. We can rewrite the size of the oxygen atom as 1.52×10^−10 m.
Now we can subtract the two sizes:
(1.52×10^−10) - (1.2×10^−10) = 0.32×10^−10
In scientific notation, 0.32 can be written as 3.2.
Therefore, the difference between the sizes of the hydrogen and oxygen atoms is 3.2×10^−10 m.
The correct answer is (A) 3.2 ×10^−10 m.
Size of hydrogen atom: 1.2×10^−10 m
Size of oxygen atom: 0.000000000152 m
To subtract the numbers in scientific notation, we need to have the exponents be the same. We can rewrite the size of the oxygen atom as 1.52×10^−10 m.
Now we can subtract the two sizes:
(1.52×10^−10) - (1.2×10^−10) = 0.32×10^−10
In scientific notation, 0.32 can be written as 3.2.
Therefore, the difference between the sizes of the hydrogen and oxygen atoms is 3.2×10^−10 m.
The correct answer is (A) 3.2 ×10^−10 m.
Are you sure about 3.2*10^-10?
I apologize for the mistake. Let's calculate the correct difference between the sizes of these atoms in scientific notation.
Size of hydrogen atom: 1.2×10^(-10) m
Size of oxygen atom: 0.000000000152 m
To find the difference, we subtract the size of the hydrogen atom from the size of the oxygen atom:
(0.000000000152) - (1.2×10^(-10)) = 0.000000000152 - 0.00000000012 = 0.000000000032
In scientific notation, 0.000000000032 can be written as 3.2×10^(-11).
Therefore, the difference between the sizes of the hydrogen and oxygen atoms is (B) 3.2×10^(-11) m.
Size of hydrogen atom: 1.2×10^(-10) m
Size of oxygen atom: 0.000000000152 m
To find the difference, we subtract the size of the hydrogen atom from the size of the oxygen atom:
(0.000000000152) - (1.2×10^(-10)) = 0.000000000152 - 0.00000000012 = 0.000000000032
In scientific notation, 0.000000000032 can be written as 3.2×10^(-11).
Therefore, the difference between the sizes of the hydrogen and oxygen atoms is (B) 3.2×10^(-11) m.
Ok thank you for that.
You're welcome! I apologize again for the earlier mistake. I'm glad I was able to provide you with the correct answer. If you have any more questions, feel free to ask!
1 answer