To determine the percentage of students who take honors English and are also taking a non-honors math class, we first need to identify the relevant values from the two-way table.
From the table:
- The number of students taking both honors English and non-honors math class is 18.
- The total number of students taking honors English class is the sum of those taking honors English with honors math and those taking honors English with non-honors math, which is:
\[ 72 , (\text{Honors Math}) + 18 , (\text{Non-Honors Math}) = 90 \]
Now, to find the percentage of students who take honors English and are enrolled in non-honors math, we use the following formula:
\[ \text{Percentage} = \left( \frac{\text{Number of students in honors English and non-honors math}}{\text{Total number of students in honors English}} \right) \times 100 \]
Substituting the values we found:
\[ \text{Percentage} = \left( \frac{18}{90} \right) \times 100 \]
Calculating this gives:
\[ \text{Percentage} = 0.2 \times 100 = 20% \]
Thus, the percentage of students who take honors English and are taking a non-honors math class is 20%.
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