If the 3rd side has length 2x, then the altitude h is
x^2 + h^2 = 13^2
x dx/dt + h dh/dt = 0
when h=12, you have a 5-12-13 right triangle, so
5 * 24/2 + 12 dh/dt = 0
dh/dt = -60/12 = -5 in/min
The two equal sides of an isosceles triangle are each equal to 13 inches. If the third side is
increasing at 24 in/min, at what is the altitude drawn to this side changing when the altitude is
12 inches?
2 answers
we have the same conclusion and yet the correct answer written on our book is -1/2 in/min?? I don't know how