The trajectory of a ball thrown in the air is given by h(t)= −4t2+16t−10 , where h is the height in metres and t is the time in seconds. How long is the ball above 2 meters?

Answer 1

see "help quickkkk"

Answer 2

-4t^2+16t-10 > 2
t^2 - 4t + 3 < 0
(t-1)(t-3) < 0
So, what do you think?