the track at the park is 2 3/5 long steves bike tire was flat 3/4 of the way around the track how far did steve travel before he got a flat tire

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To find out how far Steve traveled before his tire went flat, we need to calculate \( \frac{3}{4} \) of the total length of the track, which is \( 2 \frac{3}{5} \).

First, let's convert \( 2 \frac{3}{5} \) into an improper fraction:

\[ 2 \frac{3}{5} = \frac{2 \times 5 + 3}{5} = \frac{10 + 3}{5} = \frac{13}{5} \]

Now we can calculate \( \frac{3}{4} \) of \( \frac{13}{5} \):

\[ \frac{3}{4} \times \frac{13}{5} = \frac{3 \times 13}{4 \times 5} = \frac{39}{20} \]

Next, let's convert \( \frac{39}{20} \) into a mixed number:

\[ \frac{39}{20} = 1 \frac{19}{20} \]

Thus, Steve traveled \( 1 \frac{19}{20} \) units around the track before he got a flat tire.

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