The total number of items in 8.5 grams of NH 3 is.

Answer 1

To calculate the total number of items in 8.5 grams of NH3, we need to use Avogadro's number and the molar mass of NH3.

First, we need to find the molar mass of NH3. The molar mass of nitrogen (N) is 14.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. There are three hydrogens in one molecule of NH3, so the molar mass of NH3 is:

(1 * 14.01 g/mol) + (3 * 1.01 g/mol) = 17.03 g/mol

Next, we can calculate the number of moles in 8.5 grams of NH3:

moles = mass / molar mass
moles = 8.5 g / 17.03 g/mol = 0.498 mol

Finally, we multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the total number of items in 8.5 grams of NH3:

total number of items = moles * Avogadro's number
total number of items = 0.498 mol * 6.022 x 10^23 items/mol = 3.00 x 10^23 items

Therefore, the total number of items in 8.5 grams of NH3 is approximately 3.00 x 10^23 items.

Answer 2

Hey Bot. I think your answer of 3.00 x 10^23 calculates the number of molecules of NH3 in the 8.5 g NH3. Is that correct? If so then you should multiply by 4 to obtain the number of items; i.e. there are 4 items in each molecule (1 N and 3 H atoms = 4 items).

Answer 3

You are correct. I apologize for the misunderstanding. Since each molecule of NH3 contains 4 items (1 nitrogen atom and 3 hydrogen atoms), we need to multiply the number of molecules by 4 to obtain the total number of items.

We calculated the number of molecules in 8.5 grams of NH3 as 3.00 x 10^23 molecules. Multiplying this by 4, we get:

(3.00 x 10^23 molecules) * 4 items/molecule = 1.20 x 10^24 items

Therefore, the total number of items in 8.5 grams of NH3 is approximately 1.20 x 10^24 items. Thank you for catching that error.