Here are the responses and calculations for each question:
Question 1:
Total room cost for two nights: $456.84
Cost per night:
\[ \text{Cost per night} = \frac{456.84}{2} = 228.42 \]
Cost per person for one night (split four ways):
\[ \text{Cost per person} = \frac{228.42}{4} = 57.11 \]
Answer: $57.11
Question 2:
Time spent by two friends: Each spends \( \frac{5}{6} \) of an hour.
Total time:
\[ \text{Total time} = 2 \times \frac{5}{6} = \frac{10}{6} = \frac{5}{3} \text{ hours} \]
This is equivalent to 1 hour and \( \frac{2}{3} \) of an hour (since \( \frac{2}{3} \) is 40 minutes).
Answer: 1 \( \frac{2}{3} \) hours
Question 3:
Pizzas received:
You get \( \frac{1}{3} \) of a pizza and another friend gets \( \frac{1}{2} \) of a pizza.
To find the common denominator, we use 6:
- You: \( \frac{1}{3} = \frac{2}{6} \)
- Friend: \( \frac{1}{2} = \frac{3}{6} \)
Total pizza given away:
\[ \text{Total given} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6} \]
Total pizza ordered: 2 pizzas
Pizza left over:
\[ \text{Pizza left} = 2 - \frac{5}{6} = \frac{12}{6} - \frac{5}{6} = \frac{7}{6} = 1 \frac{1}{6} \text{ pizzas} \]
Answer: 1 \( \frac{1}{6} \) pizzas
Question 4:
Option A Area:
\[ A_A = 4 \frac{1}{3} \times 7 \frac{1}{8} \]
Convert to improper fractions:
\[ 4 \frac{1}{3} = \frac{13}{3}, ; 7 \frac{1}{8} = \frac{57}{8} \]
\[ A_A = \frac{13}{3} \times \frac{57}{8} = \frac{741}{24} \text{ square feet} \]
Option B Area:
\[ A_B = 5.2 \times 6.8 = 35.36 \text{ square feet} \]
Comparing Areas:
Convert \( \frac{741}{24} \) to decimal:
\[ \frac{741}{24} \approx 30.875 \text{ square feet} \]
Answer: Option B is the larger area since \( 35.36 > 30.875 \).
Question 5:
For this question, please provide any specific calculations or written work you would like to attach regarding Task 3: The Hotel.
Please let me know if there is anything more specific you want to go over for each question!